In an instrument, there are 25 divisions on the vernier scale which coincide with 24th division of the main scale. 1 cm on main scale is divided in 20 equal parts. The least count of the instrument is
- In an instrument, there are 25 divisions on the vernier scale which coincide with 24th division of the main scale. 1 cm on main scale is divided in 20 equal parts. The least count of the instrument is
- 0.002 cm
- 0.05 cm
- 0.001 cm
- 0.02 cm
Ans. As we know that the least count of a vernier calipers is
= the value of smallest division of main scale / number of divisions of vernier scale
= (1 cm / 20) / 25
= (10 mm / 20) / 25
= 0.5 mm / 25
= 0.02 mm
= 0.002 cm
Therefore, option 1 that is 0.002 cm is correct.
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